I have this equation

k = (a b c t)/(Sqrt[(f + t)^2])

and I want to set

p = t/(t + f)

In which way I can eliminate t/(t+f)?

I tried this:

FullSimplify[K, TransformationFunctions -> {(# /. t/(t + f) -> p &), Automatic}]

But it did not work.

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– Michael E2

Jan 27 at 3:38

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2 Answers

2

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Eliminate[{

k == (a b c t)/(Sqrt[(f + t)^2]),

p == t/(t + f)

},

{t, f}]

a^2 b^2 c^2 p^2 == k^2

k = (a b c t)/(Sqrt[(f + t)^2]);

Assuming that {t > 0, p > 0}

Simplify[k /. t + f -> t/p, {t > 0, p > 0}]

(* a b c p *)

Or,

Simplify[k /. f -> t (1 – p)/p, {t > 0, p > 0}]

(* a b c p *)

Or, assuming {0 <= p < 1, f > 0}

Simplify[k /. t -> f p/(1 – p), {0 <= p < 1, f > 0}]

(* a b c p *)