# limit of the ratio of two functions of log(x) as x goes to 0 from the positive-x side?

What assumptions, if any, are required such that the following limit is correct?

limx→0+alog(x)blog(x)=ablimx→0+alog(x)blog(x)=ab\lim_{x \rightarrow 0^+}{\frac{a \log(x)}{b \log(x)} } = \frac{a}{b}

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What needed is b≠0b≠0b\ne 0.
– Ng Chung Tak
2 days ago

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